AP EAMCET · Maths · Probability
In a random experiment, two dice are thrown and the sum of the numbers appeared on them is recorded. This experiment is repeated 9 times. If the probability that a sum of 6 appears at least once is \(\mathrm{P}_1\) and a sum of 8 appears at least once is \(\mathrm{P}_2\), then \(\mathrm{P}_1: \mathrm{P}_2=\)
- A \(4: 3\)
- B \(3: 1\)
- C \(1: 2\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(D) \(1: 1\)
Step-by-step Solution
Detailed explanation
\(P_1=\left(\frac{6}{36}\right)^9, P_2=\left(\frac{6}{36}\right)^9 \quad \therefore P_1: P_2=1: 1\)
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