AP EAMCET · Maths · Ellipse
The equation of the ellipse with its focus at \((6,2)\) centre at \((1,2)\) and which passes through the point \((4,6)\) is
- A \(\frac{(x-1)^2}{25}+\frac{(y-2)^2}{16}=1\)
- B \(\frac{(x-1)^2}{25}+\frac{(y-2)^2}{20}=1\)
- C \(\frac{(x-1)^2}{45}+\frac{(y-1)^2}{16}=1\)
- D \(\frac{(x-1)^2}{45}+\frac{(y-2)^2}{20}=1\)
Answer & Solution
Correct Answer
(D) \(\frac{(x-1)^2}{45}+\frac{(y-2)^2}{20}=1\)
Step-by-step Solution
Detailed explanation
Given, Focus \(\mathrm{S}=(6,2)\) Centre \(\mathrm{C}=(1,2)=(h, k)\) say Point \(\mathrm{P}=(4,6)\) Required Equation of ellipse is \(\frac{(x-1)^2}{a^2}+\frac{(y-2)^2}{b^2}=1\) ...(i) Since, Eq. (i) passes through \(\mathrm{P}(4,6)\)…
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