AP EAMCET · Maths · Straight Lines
Suppose the pairs of straight lines \(2 x^2+a x y+3 y^2=0\) and \(2 x^2+b x y-3 y^2=0\) are such that they have one common line with the other two remaining perpendicular. Then the values of \(a\) and \(b\) respectively are
- A \(-5,1\)
- B \(5,-1\)
- C 5,1
- D \(5, \frac{1}{5}\)
Answer & Solution
Correct Answer
(C) 5,1
Step-by-step Solution
Detailed explanation
For \(a x^2+2 h x y+b y^2=0\) ...(i) If the slope of 2 lines representing ...(i) are \(m_1\) and \(m_2\) then \(\begin{aligned} & m_1+m_2=-2 h / b \\ & m_1 \cdot m_2=a / b\end{aligned}\) For \(2 x^2+a x y+3 y^2=0\) ...(ii) If slope of common line is \(m\) and slope of other 2…
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