AP EAMCET · Maths · Straight Lines
Suppose P(x,y)lying on \(\sqrt{3} x-y+2=0\) or \(\sqrt{3} x+y-2=0\)
is at a distance of 5 units from their point of intersection. Then the distance from \((0,0)\) to the foot of the perpendicular of \(P\) onto the \(y\)-axis is
- A \(2\)
- B \(\frac{5 \sqrt{3}}{2}\)
- C \(2+\frac{5 \sqrt{3}}{2}\)
- D \(2-\frac{5 \sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{L}_1: \sqrt{3} x-y+2=0\)…
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