AP EAMCET · Maths · Differential Equations
Solve the following differential equation
\[
\left(x^2+1\right) \frac{d y}{d x}+4 x y=\frac{1}{x^2+1}
\]
- A \(y\left(x^2-1\right)^2=x+c\)
- B \(y\left(x^2+1\right)^2=x+c\)
- C \(y\left(x^2+1\right)^2=x^2+c\)
- D \(y\left(x^2-1\right)^2=x^2+c\)
Answer & Solution
Correct Answer
(B) \(y\left(x^2+1\right)^2=x+c\)
Step-by-step Solution
Detailed explanation
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