AP EAMCET · Maths · Permutation Combination
The number of ways of distributing 3 dozen fruits (no two fruits are identical) to 9 persons such that each gets the same number of fruits is
- A \(\frac{36!}{(9!)^4}\)
- B \(\frac{36!}{(4!)^9}\)
- C \({ }^{36} \mathrm{P}_9 \times 4!\)
- D \(\frac{36!}{4!(9!)^4}\)
Answer & Solution
Correct Answer
(B) \(\frac{36!}{(4!)^9}\)
Step-by-step Solution
Detailed explanation
Total fruits = \( 3 \times 12 = 36 \) Each person gets = \( \frac{36}{9} = 4 \) fruits. Number of ways = \( \binom{36}{4} \binom{32}{4} \binom{28}{4} \dots \binom{4}{4} \) Number of ways =…
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