AP EAMCET · Maths · Permutation Combination
\(S_1, S_2, \ldots \ldots, S_{10}\) are the speakers in a conference. If \(S_1\) addresses only after \(S_2\), then the number of ways the speakers address is
- A \(10 !\)
- B \(9 !\)
- C \(10 \times 8 !\)
- D \(\frac{(10 !)}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{(10 !)}{2}\)
Step-by-step Solution
Detailed explanation
Since, \(S_1\) speak after \(S_2\), therefore two places can be chosen out of 10 place is \({ }^{10} C_2\) ways and rest of the 8 speakers can speak in 8 ! ways. \(\therefore\) Required number of ways \(={ }^{10} C_2 \cdot 8\) !…
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