AP EAMCET · Maths · Complex Number
\(\left(\frac{1-i}{1+i}\right)^{2022}+\left(\frac{1+i}{1-i}\right)^{2021}=\)
- A \(-\mathrm{i}\)
- B \(\mathrm{i}\)
- C \(\mathrm{i}+1\)
- D \(\mathrm{i}-1\)
Answer & Solution
Correct Answer
(D) \(\mathrm{i}-1\)
Step-by-step Solution
Detailed explanation
\(\left(\frac{1-i}{1+i}\right)^{2022}+\left(\frac{1+i}{1-i}\right)^{2021}\)…
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