AP EAMCET · Maths · Complex Number
The product of real roots of the equation \(4 x^4-24 x^3+\) \(57 \mathrm{x}^2+18 \mathrm{x}-45=0\) if one of the root is \(3+i \sqrt{6}\) is
- A \(-5 / 16\)
- B \(5 / 16\)
- C \(3 / 4\)
- D \(-3 / 4\)
Answer & Solution
Correct Answer
(D) \(-3 / 4\)
Step-by-step Solution
Detailed explanation
Given that \(3+i \sqrt{6}\) is one roots therefore \(3-i \sqrt{6}\) is also a root .Let \(\alpha\) and \(\beta\) are other two real roots…
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