AP EAMCET · Maths · Functions
Match the following
\(\begin{array}{|c|c|c|}
\hline & \text { List I } & \text { List II } \\
\hline \text { (A) } & \begin{array}{l}
f: R \rightarrow R \text { is such that } f(x)=p x+q \\
(p \neq 0), \forall x \in R
\end{array} & \begin{array}{l}
\text {I. } f \text { is neither one-one nor onto }
\end{array} \\
\hline \text { (B) } & \begin{array}{l}
f: R \rightarrow R^{+} \cup\{0\} \text { is such that } f(x)=x^2, \forall x \in R
\end{array} & \begin{array}{l}
\text {II. } f \text { is both one-one and onto }
\end{array} \\
\hline \text { (C) } & \begin{array}{l}
f: N \rightarrow N \text { is such that } f(n)=n^2+2 n+3, \forall n \in N
\end{array} & \begin{array}{l}
\text {III. } f \text { is one-one but not onto }
\end{array} \\
\hline \text { (D) } & \begin{array}{l}
f: R \rightarrow R \text { is such that } f(x)=2\left(\cos ^2 5 x+\sin ^2 5 x\right) \\
\forall x \in R
\end{array} & \begin{array}{l}
\text {IV. } f \text { is onto but not one-one }
\end{array} \\
\hline && V. f \text{ is a constant function and also a bijection} \\
\hline
\end{array}\)
The correct answer is
- A \(\begin{array}{cc} & A & B & C & D \\ & II & IV & III & I \\ \end{array}\)
- B \(\begin{array}{cc} & A & B & C & D \\ & II & IV & V & I \\ \end{array}\)
- C \(\begin{array}{cc} & A & B & C & D \\ & II & I & III & V \\ \end{array}\)
- D \(\begin{array}{cc} & A & B & C & D \\ & III & II & I & IV \\ \end{array}\)
Answer & Solution
Correct Answer
(A) \(\begin{array}{cc} & A & B & C & D \\ & II & IV & III & I \\ \end{array}\)
Step-by-step Solution
Detailed explanation
(A) For function \(f: R \rightarrow R\) is defined as \(f(x)=p x+q,(p \neq 0)\) is a linear function.] And linear functions are one-one and onto in set of real numbers \((R)\). So, \(\mathrm{A} \rightarrow \mathrm{II}\) (B) For function \(f: R \rightarrow R^{+} \cup\{0\}\) is…
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