AP EAMCET · Maths · Functions
Let \([\mathrm{x}]\) represent the greatest integer less than or equal to \(\mathrm{x},\{\mathrm{x}\}=\mathrm{x}-[\mathrm{x}]\), \(\sqrt{2}=1.414\) and \(\sqrt{3}=1.732\). If \(f(x)=\left\{x+\left[\frac{x}{1+x^2}\right]\right\}\) is a real valued function, then \(\mathrm{f}(\sqrt{2})+\mathrm{f}(-\sqrt{3})=\)
- A \(0.682\)
- B \(0.318\)
- C \(0.146\)
- D \(1.146\)
Answer & Solution
Correct Answer
(A) \(0.682\)
Step-by-step Solution
Detailed explanation
\(\left[\frac{\sqrt{2}}{1+(\sqrt{2})^2}\right] = \left[\frac{\sqrt{2}}{3}\right] = [0.471] = 0\) \(f(\sqrt{2}) = \{\sqrt{2}+0\} = \{\sqrt{2}\} = \sqrt{2}-[\sqrt{2}] = \sqrt{2}-1 = 1.414-1 = 0.414\)…
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