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AP EAMCET · Maths · Hyperbola

Let \(x^2+y^2=16\) be the equation of the auxiliary circle of a hyperbola \(\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\) and let \((4 \sqrt{2}, 3)\) be a point on the hyperbola. Then, the eccentricity of the hyperbola is

  1. A \(5 / 4\)
  2. B \(5 / 3\)
  3. C \(4 / 3\)
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(A) \(5 / 4\)

Step-by-step Solution

Detailed explanation

The auxiliary circle of a hyperbola \(\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\) is \(x^2+y^2=a^2\). \[ \therefore \quad a^2=16 \Rightarrow a=4 \] The hyperbola passes through \((4 \sqrt{2}, 3)\)…