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AP EAMCET · Maths · Vector Algebra

Let x, y are real numbers. If a=(sinx)i^+(siny)j^ and b=(cosx)i^+(cosy)j^, then |a×b| is

  1. A 0
  2. B Greater than one
  3. C Less than or equal to 1
  4. D Less than 1
Verified Solution

Answer & Solution

Correct Answer

(C) Less than or equal to 1

Step-by-step Solution

Detailed explanation

Given, a→=(sinx)i^+(siny)j^ and b→=(cosx)i^+(cosy)j^ Then, a→×b→=sinxcosy-cosxsinyk^=sinx-yk^ Now, a→×b→=sin2x-y=sinx-y We know that value of sine lies between -1, 1 ⇒a→×b→≤1