AP EAMCET · Maths · Indefinite Integration
Let the equation of the curve passing through the point \((0,1)\) be given by \(y=\int x^3 e^{x^4} d x\). If the equation of the curve is written in the form \(x=f(y)\), then \(f(y)=\)
- A \(\log |4 y-3|\)
- B \((\log |4 y-3|)^{1 / 4}\)
- C \(\left(\log \left|\frac{3-4 y}{4}\right|\right)^{1 / 4}\)
- D \(\log \left|\frac{4 y-3}{4}\right|\)
Answer & Solution
Correct Answer
(B) \((\log |4 y-3|)^{1 / 4}\)
Step-by-step Solution
Detailed explanation
It is given that, \(y=\int x^3 e^{x^4} d x\) Let \(x^4=t \Rightarrow 4 x^3 d x=d t\) \(\therefore\) So, \(y=\frac{1}{4} \int e^t d t=\frac{e^t}{4}+C=\frac{e^{x^4}}{4}+C\) \(\because\) The curve \(y=\frac{e^{x^4}}{4}+C\) passes through point \((0,1)\), so…
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