AP EAMCET · Maths · Probability
If \(A\) and \(B\) are two events such that \(P(B) \neq 0\) and \(P(B) \neq 1\), then \(P(\bar{A} \mid \bar{B})\) is
- A \(1-P(A \mid B)\)
- B \(1-P(\bar{A} \mid B)\)
- C \(\frac{1-P(A \cup B)}{P(\bar{B})}\)
- D \(\frac{P(\bar{A})}{P(\bar{B})}\)
Answer & Solution
Correct Answer
(C) \(\frac{1-P(A \cup B)}{P(\bar{B})}\)
Step-by-step Solution
Detailed explanation
\(P(\bar{A} \mid \bar{B})=\frac{P(\bar{B} \cap \bar{A})}{P(B)}=\frac{1-P(A \cup B)}{P(B)}\)
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