AP EAMCET · Maths · Circle
Let \(\mathrm{S}\) be a circle concentric with the circle \(3 x^2+3 y^2+x+y-1=0\). If the length of the tangent drawn from a point \((2,-2)\) to the given circle is the radius of the circle S, then the power of the point \((2,1)\) with respect to the circle \(\mathrm{S}\) is
- A \(\frac{-137}{18}\)
- B \(\frac{1}{18}\)
- C \(\frac{-29}{18}\)
- D \(\frac{23}{18}\)
Answer & Solution
Correct Answer
(C) \(\frac{-29}{18}\)
Step-by-step Solution
Detailed explanation
Given circle is \(3 x^2+3 y^2+x+y-1=0\) \[ \begin{aligned} & \Rightarrow x^2+y^2+\frac{1}{3} x+\frac{1}{3} y-\frac{1}{3}=0 \\ & \therefore \text { Centre }=\left(-\frac{1}{6},-\frac{1}{6}\right), \text { radius }=\frac{\sqrt{14}}{6} \end{aligned} \] Length of tangents \(P A\),…
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