AP EAMCET · Maths · Area Under Curves
If the area of the region enclosed by the curve \(x^2+y^2=16\) and then lines \(x=2\) and \(x=3\) is \(\left(3 \sqrt{7}-4 \sqrt{3}-\frac{8 \pi}{3}+k\right)\) sq units, then \(k\) equals
- A \(16 \sin ^{-1}\left(\frac{3}{4}\right)\)
- B \(8 \sin ^{-1}\left(\frac{3}{4}\right)\)
- C \(4 \sin ^{-1}\left(\frac{3}{4}\right)\)
- D \(2 \sin ^{-1}\left(\frac{3}{4}\right)\)
Answer & Solution
Correct Answer
(A) \(16 \sin ^{-1}\left(\frac{3}{4}\right)\)
Step-by-step Solution
Detailed explanation
Area of region enclosed by the curve \(x^2+y^2=16\) and line \(x=2\) and \(x=3\) is…
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