AP EAMCET · Maths · Probability
Given that a throw of three unbiased dice shows different faces, what is the probability that their total is eight?
- A \(\frac{1}{10}\)
- B \(\frac{23}{256}\)
- C \(\frac{13}{36}\)
- D \(\frac{17}{20}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{10}\)
Step-by-step Solution
Detailed explanation
Number of ways to get different faces on the a throw of three unbiased dice are \({ }^6 C_3=\frac{6 \times 5 \times 4}{3 \times 2}=20\) and the number of ways to get their total is eight \((1,2,5),(1,3,4)\) only. So, the required probability \(=\frac{2}{20}=\frac{1}{10}\) Hence,…
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