AP EAMCET · PHYSICS · Thermal Properties of Matter
A small quantity of water of mass ' m ' at temperature \(\theta^{\circ} \mathrm{C}\) is mixed with a large mass ' M ' of ice which is at its melting point. If ' s ' is specific heat capacity of water and ' \(L\) ' is the Latent heat of fusion of ice, then the mass of ice melted is
- A \(\frac{\mathrm{ML}}{\mathrm{ms} \theta}\)
- B \(\frac{\mathrm{ms} \theta}{\mathrm{ML}}\)
- C \(\frac{\mathrm{Ms} \theta}{\mathrm{L}}\)
- D \(\frac{\mathrm{ms} \theta}{\mathrm{L}}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{ms} \theta}{\mathrm{L}}\)
Step-by-step Solution
Detailed explanation
\(Q_{\text{lost by water}} = Q_{\text{gained by ice}}\) \(ms\theta = m_{\text{melted}} L\) \(m_{\text{melted}} = \frac{ms\theta}{L}\)
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