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AP EAMCET · PHYSICS · Thermal Properties of Matter

A small quantity of water of mass ' m ' at temperature \(\theta^{\circ} \mathrm{C}\) is mixed with a large mass ' M ' of ice which is at its melting point. If ' s ' is specific heat capacity of water and ' \(L\) ' is the Latent heat of fusion of ice, then the mass of ice melted is

  1. A \(\frac{\mathrm{ML}}{\mathrm{ms} \theta}\)
  2. B \(\frac{\mathrm{ms} \theta}{\mathrm{ML}}\)
  3. C \(\frac{\mathrm{Ms} \theta}{\mathrm{L}}\)
  4. D \(\frac{\mathrm{ms} \theta}{\mathrm{L}}\)
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Answer & Solution

Correct Answer

(D) \(\frac{\mathrm{ms} \theta}{\mathrm{L}}\)

Step-by-step Solution

Detailed explanation

\(Q_{\text{lost by water}} = Q_{\text{gained by ice}}\) \(ms\theta = m_{\text{melted}} L\) \(m_{\text{melted}} = \frac{ms\theta}{L}\)
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