AP EAMCET · Maths · Vector Algebra
Let \(\overrightarrow{\mathrm{OA}}=2 \hat{\mathrm{i}}-3 \hat{\mathrm{j}}+\hat{\mathrm{k}}, \overrightarrow{\mathrm{OB}}=\hat{\mathrm{i}}-4 \hat{\mathrm{j}}-3 \hat{\mathrm{k}}\) and \(\overrightarrow{\mathrm{OC}}=-3 \hat{\mathrm{i}}+\hat{\mathrm{j}}+2 \hat{\mathrm{k}}\) be the position vectors of three points, \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) respectively. If \(\mathrm{G}\) is the centroid of triangle \(\mathrm{ABC}\), then \(\mathrm{BC}^2+\mathrm{CA}^2+\mathrm{AB}^2+9(\mathrm{OG})^2=\)
- A 162
- B 156
- C 144
- D 132
Answer & Solution
Correct Answer
(A) 162
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Position vector of centroid }=\overrightarrow{\mathrm{OG}}=\frac{\overrightarrow{\mathrm{OA}}+\overrightarrow{\mathrm{OB}}+\overrightarrow{\mathrm{OC}}}{3} \\ & \Rightarrow \overrightarrow{\mathrm{OG}}=-2^{\wedge} \end{aligned} \] Now…
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