AP EAMCET · Maths · Pair of Lines
The equation of pair of straight lines parallel to \(X\)-axis and touching the circle \(x^2+y^2-6 x-4 y-12=0\)
- A \(y^2-4 y-21=0\)
- B \(y^2+4 y-21=0\)
- C \(y^2-4 y+21=0\)
- D \(y^2+4 y+21=0\)
Answer & Solution
Correct Answer
(A) \(y^2-4 y-21=0\)
Step-by-step Solution
Detailed explanation
Given circle is \(x^2+y^2-6 x-4 y-12=0\) \[ \begin{aligned} \text { Centre } & =(3,2) \\ \text { Radius } & =\sqrt{(3)^2+(2)^2+12}=\sqrt{9+4+12}=\sqrt{25} \\ r & =5 \end{aligned} \] Since, tangents are paralle to \(X\)-axis \(\therefore\) Let \(y=k\) be the tangent to the given…
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