AP EAMCET · Chemistry · p Block Elements (Group 13 & 14)
A compound \(X\), of boron reacts with \(\mathrm{NH}_3\) on heating to give another compound \(Y\), which is called inorganic benzene. The compound \(X\) can be prepared by treating \(\mathrm{BF}_3\) with lithium aluminium hydride. The compounds \(X\) and \(Y\) are represented by the formulas.
- A \(\mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6\)
- B \(\mathrm{B}_2 \mathrm{O}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6\)
- C \(\mathrm{BF}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6\)
- D \(\mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6, \mathrm{~B}_2 \mathrm{H}_6\)
Answer & Solution
Correct Answer
(A) \(\mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6\)
Step-by-step Solution
Detailed explanation
\(\mathrm{BF}_3 \xrightarrow[-\mathrm{LiF},-\mathrm{AlF}_3]{\mathrm{LiAlH}_4} \underset{(X)}{\mathrm{B}_2 \mathrm{H}_6} \xrightarrow[-\mathrm{H}_2]{\mathrm{NH}_3 / \Delta} \underset{(Y)}{\mathrm{B}_3 \mathrm{~N}_3 \mathrm{H}_6}\) \((X) \Rightarrow \mathrm{B}_2 \mathrm{H}_6\)…
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