AP EAMCET · Maths · Probability
If all the letters of the word 'SENSELESSNESS' are arranged in all possible ways and an arrangement among them is chosen at random then, the probability that all the E's come together in that arrangement is
- A \(\frac{1}{990}\)
- B \(\frac{2}{143}\)
- C \(\frac{1}{120}\)
- D \(\frac{1}{429}\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{143}\)
Step-by-step Solution
Detailed explanation
Total words can be made out of 'SENSELESSNESS' \(=\frac{13!}{6!4!2!}=180180\) Total words can be made with all the \(E\) 's together \(=\frac{(13-3)!}{6!2!}=2520\) \(\therefore\) Required probability \(=\frac{2520}{180180}=\frac{2}{143}\).
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