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AP EAMCET · Maths · Vector Algebra

Let \(A B C D E F\) be a regular hexagon with the vertices \(A, B, C, D, E\) and \(F\) counter clockwise. Then, the vector \(\mathbf{A B}+\mathbf{B C}\) is equal parallel to

  1. A \(B C+C D\)
  2. B \(C D+D E\)
  3. C \(A F+F E\)
  4. D \(F E+E D\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(F E+E D\)

Step-by-step Solution

Detailed explanation

\[ \begin{aligned} \mathbf{A B}+\mathbf{B C} & =\mathbf{A C} \\ \text { and } \mathbf{F E}+\mathbf{E D} & =\mathbf{F D} \end{aligned} \] Since, \(A B C D E F\) is regular hexagon. AC must be parallel to FD. \(\therefore \mathbf{A B}+\mathbf{B C}\) is parallel to…