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AP EAMCET · Maths · Functions

[.] represents greatest integer function. Let \(g(x)=1+x-[x]\) and \(f(x)=\left\{\begin{array}{cl}-3, & x < 0 \\ 0, & x=0, \text { then } \\ 5, & x>0\end{array}\right.\) \(f(g(x))\) is

  1. A \(f(x)\)
  2. B \(-15\)
  3. C \(5\)
  4. D \(-3\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(5\)

Step-by-step Solution

Detailed explanation

We have, \(g(x)=1+x-[x]\) \(g(x)=1+\{x\} \quad[\because x-[x]=\{x\}]\) \(\Rightarrow g(x) \in[1,2) \quad[\because\{x\} \in[0,1)]\) Now, \(f(x)=\left\{\begin{array}{cc}-3, & x 0\end{array}\right.\) \(\therefore \quad f(g(x))=5 ; g(x) \geq 1\)