AP EAMCET · Maths · Vector Algebra
Let \(\vec{a}=\hat{i}+\hat{j}+\hat{k}, \vec{b}=\hat{i}+\hat{j}-2 \hat{k}, \vec{c}=\hat{i}-2 \hat{j}+3 \hat{k}\) and \(\overrightarrow{\mathrm{d}}=-4 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}-3 \hat{\mathrm{k}}, \overrightarrow{\mathrm{d}}=x(\overrightarrow{\mathrm{b}} \times \overrightarrow{\mathrm{c}})-\frac{7}{9}(\overrightarrow{\mathrm{c}} \times \overrightarrow{\mathrm{a}})+\mathrm{z}(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}})\), then \(x=\)
- A \(\frac{-7}{9}\)
- B \(\frac{2}{9}\)
- C \(\frac{23}{9}\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{9}\)
Step-by-step Solution
Detailed explanation
\(\vec{b} \times \vec{c}=\left|\begin{array}{lll}\hat{i} & \hat{j} & \hat{k} \\ 1 & 1 & -2 \\ 1 & -2 & 3\end{array}\right|=\hat{i}(-1)-\hat{j}(5)+\hat{k}(-3)\)…
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