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AP EAMCET · Maths · Vector Algebra

Let \(\mathbf{a}, \mathbf{b}\) and \(\mathbf{c}\) be the three vectors. If \(|\mathbf{a}|=1\), \(|\mathbf{b}|=17\) and \(|\mathbf{c}|=8\) and the angle between \(\mathbf{a}\) and \(\mathbf{b}\) is \(\theta\) and \(\mathbf{a} \times(\mathbf{a} \times \mathbf{b})-\mathbf{c}=0\), then \(\cos \theta+\operatorname{cosec} \theta\) is equal to

  1. A \(\frac{409}{136}\)
  2. B \(\frac{309}{136}\)
  3. C \(\frac{419}{126}\)
  4. D \(\frac{409}{126}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{409}{136}\)

Step-by-step Solution

Detailed explanation

Given, \(|\mathbf{a}|=1,|\mathbf{b}|=17\) and \(|\mathbf{c}|=8\) Angle between \(\mathbf{a}\) and \(\mathbf{b}\) is \(\theta\). \(\mathbf{a} \times(\mathbf{a} \times \mathbf{b})-\mathbf{c}=0\)…