AP EAMCET · Maths · Three Dimensional Geometry
Find the equation of a plane, given that the foot of perpendicular drawn to the plane from origin is \((2,1,2)\).
- A \(3 x+y+z=6\)
- B \(x+y+z-5=0\)
- C \(2 x-y-2 z=-1\)
- D \(2 x+y+2 z=9\)
Answer & Solution
Correct Answer
(D) \(2 x+y+2 z=9\)
Step-by-step Solution
Detailed explanation
Given, foot of perpendicular drawn from origin to the plane is \((2,1,2)\). \(\because\) Equation of plane \[ (\mathbf{r}-\mathbf{a}) \cdot \mathbf{n}=0 \] where, \(\mathbf{a}=\) Position vector of point on the plane \[ \mathbf{n}=\text { normal vector } \] Now here,…
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