AP EAMCET · Maths · Matrices
Let \(A=\left(\begin{array}{c}0 \\ -6 \\ 8\end{array}\right), B=\left(\begin{array}{ccc}3 & 5 & -7 \\ 0 & -1 & 8 \\ 6 & -1 & 0\end{array}\right)\) and \(X=\left(\begin{array}{l}x \\ y \\ z\end{array}\right)\). If \(\mathrm{D}=[\alpha \beta \gamma]^{\mathrm{T}}\) is the solution of \(\mathrm{X}^{\mathrm{T}} \mathrm{B}^{\mathrm{T}}=\mathrm{A}^{\mathrm{T}}\), then \(\mathrm{D}^{\mathrm{T}} \mathrm{A}=\)
- A 0
- B 4
- C -2
- D 6
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \because X^T B^T=A^T \\ & \Rightarrow\left(X^T B^T\right)=A^T \Rightarrow B X=A \\ & |B|=\left|\begin{array}{ccc}3 & 5 & -7 \\ 0 & -1 & 8 \\ 6 & -1 & 0\end{array}\right|=222, \quad B^{-1}=\frac{1}{222}\left|\begin{array}{lll}8 & 7 & 33 \\ 48 & 42 &…
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