AP EAMCET · Maths · Vector Algebra
For \(a \in R\), if the vectors \(\bar{p}=(a+1) \bar{i}+a \bar{j}+a \bar{k}, \overline{\mathrm{q}}=\mathrm{a} \overline{\mathrm{i}}+(\mathrm{a}+1) \overline{\mathrm{j}}+\mathrm{a} \overline{\mathrm{k}}\) and \(\bar{r}=a \bar{i}+a \bar{j}+(a+1) \bar{k}\) are coplanar and \(3(\bar{p} \cdot \bar{q})^2-\lambda|\bar{r} \times \bar{q}|^2=0\), then the value of \(\lambda\) is
- A \(\frac{2}{3}\)
- B \(\frac{3}{2}\)
- C 2
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
\( \begin{vmatrix} a+1 & a & a \\ a & a+1 & a \\ a & a & a+1 \end{vmatrix} = 0 \) \( (3a+1) \begin{vmatrix} 1 & a & a \\ 1 & a+1 & a \\ 1 & a & a+1 \end{vmatrix} = 0 \) \( (3a+1) \cdot 1 = 0 \Rightarrow a = -\frac{1}{3} \)…
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