AP EAMCET · Maths · Vector Algebra
Let \(\bar{a}=a_1 \hat{i}+a_2 \hat{j}+a_3 \hat{k}\) where \(\mathrm{a}_1, \mathrm{a}_2, \mathrm{a}_3\) and \(|\bar{a}|\) are rational numbers. If \(\bar{a}\) makes an angle \(45^{\circ}\) with \(\bar{b}\) and \(\bar{b}=\sqrt{2} \hat{i}+3 \sqrt{2} \hat{j}+4 \hat{k}\) then \(\bar{a}\) lies in
- A \(X Y\) - plane
- B YZ - plane
- C \(\mathrm{XZ}\) - plane
- D along the bisector of the angle between \(\hat{k}\) and \(-\bar{b}\)
Answer & Solution
Correct Answer
(A) \(X Y\) - plane
Step-by-step Solution
Detailed explanation
Given \(\bar{a}=a_1 i+a_2 \mathrm{j}+a_3 k\) and \(\bar{b}=\sqrt{2} i+3 \sqrt{2} i+4 k\) Where, \(\mathrm{a}_1, \mathrm{a}_2, \mathrm{a}_3\) and \(|\mathrm{a}|\) are rational numbers. Now acc to question…
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