AP EAMCET · Maths · Application of Derivatives
On the curve \(y=x^3\), the point at which the tangent line is parallel to the chord joining the points \((-1,-1)\) and \((2,8)\) is
- A (1, - 1)
- B (2, 8)
- C (1, 1)
- D (3, 27)
Answer & Solution
Correct Answer
(C) (1, 1)
Step-by-step Solution
Detailed explanation
According to Lagrange's Mean value theorem, \(\because y=x^3\) is a continuous and differentiable function So, there exist \(x=\mathcal{c}\), such that \(f^{\prime}(c)=\frac{f(2)-f(-1)}{2-(-1)}\)…
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