AP EAMCET · Maths · Vector Algebra
Let \(|\vec{a}|=2,|\vec{b}|=3\) and the angle between \(\vec{a}\) and \(\vec{b}\) be \(\frac{\pi}{3}\). If a parallelogram is constructed with adjacent sides \(2 \vec{a}+3 \vec{b}\) and \(\vec{a}-\vec{b}\), then its shorter diagonal is of length
- A \(108\)
- B \(172\)
- C \(6 \sqrt{3}\)
- D \(2 \sqrt{43}\)
Answer & Solution
Correct Answer
(C) \(6 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{gathered} |\vec{a}|=2,|\vec{b}|=3, \theta=\frac{\pi}{3} \\ \vec{a} \cdot \vec{b}=|\vec{a}||\vec{b}| \cos \theta=6 \times \frac{1}{2}=3 \end{gathered}\) Diagonals are \(\vec{p}+\vec{q}\) and \(\vec{p}-\vec{q}\) where…
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