AP EAMCET · Maths · Probability
A shopkeeper buys a particular type of electric bulbs from three manufactures \(M_1, M_2\) and \(M_3\). He buys \(25 \%\) of his requirement from \(M_1, 45 \%\) from \(M_2\), and \(30 \%\) from \(M_3\). Based on past experience he found that \(2 \%\) of type \(\mathrm{M}_3\) bulbs are defective, where as only \(1 \%\) of type \(M_1\) and type \(\mathrm{M}_2\) are detective. If a bulb chosen by him at random is defective, then the probability that it was of type \(M_3\) is
- A \(\frac{5}{13}\)
- B \(\frac{6}{13}\)
- C \(\frac{7}{13}\)
- D \(\frac{8}{13}\)
Answer & Solution
Correct Answer
(B) \(\frac{6}{13}\)
Step-by-step Solution
Detailed explanation
Let \(D=\) Chosen bulbs are defective.…
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