AP EAMCET · Maths · Quadratic Equation
Let \(\tan 30^{\circ}\) and \(\tan 15^{\circ}\) be the roots of the quadratic equation \(x^2+a x+b=0\), then \(1+a-b=\)
- A \(0\)
- B \(1\)
- C \(a b\)
- D \(a^2 b^2\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \tan 15^{\circ}=\tan \left(45^{\circ}-30^{\circ}\right) \\ & =\frac{1-1 / \sqrt{3}}{1+1 / \sqrt{3}}=\frac{\sqrt{3}-1}{\sqrt{3}+1} .\end{aligned}\) Given, \(\tan 30^{\circ}\) and \(\tan 15^{\circ}\) are the roots of the equation \(x^2+a x+b=0\) \(\because\)…
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