AP EAMCET · Maths · Properties of Triangles
In a \(\triangle A B C, \cos \left(\frac{B+2 C+3 A}{2}\right)+\cos \left(\frac{A-B}{2}\right)\) is equal to
- A \(-1\)
- B \(0\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
In \(\triangle A B C\),…
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