AP EAMCET · Maths · Properties of Triangles
In triangle \(A B C, \frac{\tan A}{2}=\frac{\tan B}{3}=\frac{\tan C}{4}\), then the value of \(\sec ^2 A+\sec ^2 B+\sec ^2 C=\)
- A \(\frac{101}{8}\)
- B \(\frac{111}{8}\)
- C \(\frac{121}{8}\)
- D \(\frac{91}{8}\)
Answer & Solution
Correct Answer
(B) \(\frac{111}{8}\)
Step-by-step Solution
Detailed explanation
In a \(\triangle A B C\), it is given that \(\frac{\tan A}{2}=\frac{\tan B}{3}=\frac{\tan C}{4}=k \text { (Let) }\) \(\Rightarrow \quad \tan A=2 k, \tan B=3 k\) and \(\tan c=4 k\). Since in \(\triangle A B C\),…
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