AP EAMCET · Maths · Quadratic Equation
The sum of the real roots of the equation \(x^4-2 x^3+x-380=0\) is
- A \(-1\)
- B \(0\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
Considering the question to be, to find the roots of the equation \(x^4-2 x^3+x-380=0\) Now, by trial error method we find that \(x=5\) is a solution to the equation \(\Rightarrow \quad 5^4-2 \times 5^3+5-380=0\)…
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- Calculate \(\Delta H\) in \(\mathrm{kJ}\) for the following reaction
\[
\mathrm{C}(\mathrm{g})+\mathrm{O}_2(\mathrm{~g}) \longrightarrow \mathrm{CO}_2(\mathrm{~g})
\]
Given that,
\[
\begin{gathered}
\mathrm{H}_2 \mathrm{O}(g)+\mathrm{C}(g) \longrightarrow \mathrm{CO}(g)+\mathrm{H}_2(g) ; \\
\Delta H=+131 \mathrm{~kJ} \\
\mathrm{CO}(g)+\frac{1}{2} \mathrm{O}_2(g) \longrightarrow \mathrm{CO}_2(g) ; \\
\Delta H=-282 \mathrm{~kJ} \\
\mathrm{H}_2(g)+\frac{1}{2} \mathrm{O}_2(g) \longrightarrow \mathrm{H}_2 \mathrm{O}(g) ; \\
\Delta H=-242 \mathrm{~kJ}
\end{gathered}
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