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AP EAMCET · Maths · Definite Integration

\(\int_0^{\pi / 4} \frac{x^2}{(x \sin x+\cos x)^2} d x=\)

  1. A \(\frac{2-\pi}{2+\pi}\)
  2. B \(\frac{4-\pi}{4+\pi}\)
  3. C \(\frac{6-\pi}{6+\pi}\)
  4. D \(\frac{8-\pi}{8+\pi}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{4-\pi}{4+\pi}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { } \quad I=\int \frac{x^2}{(x \sin x+\cos x)^2} d x \\ & =\int(x \sec x)\left(\frac{x \cos x}{(x \sin x+\cos x)^2}\right) d x \\ & =x \sec x \times \frac{(-1)}{(x \sin x+\cos x)} \\ & \quad-\int(\sec x+x \sec x \tan x) \frac{-1}{(x \sin x+\cos x)} d…