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AP EAMCET · Maths · Differential Equations

If \(x d y+\left(y+y^2 x\right) d x=0\) and \(y=1\) at \(x=1\). then

  1. A \(y=\frac{x}{1+\log x}\)
  2. B \(y=\frac{1+\log x}{x}\)
  3. C \(y=x(1+\log x)\)
  4. D \(y=\frac{1}{x(1+\log x)}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(y=\frac{1}{x(1+\log x)}\)

Step-by-step Solution

Detailed explanation

Since, \(x d y+\left(y+y^2 x\right) d x=0\) \(\Rightarrow \frac{d y}{d x}+\frac{y}{x}+y^2=0...(i)\) Let \(y=\frac{1}{t} \Rightarrow \frac{d y}{d x}=-\frac{1}{t^2} \frac{d t}{d x}\)…
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