AP EAMCET · Maths · Binomial Theorem
Assuming \(x\) to be so small that \(x^2\) and higher powers of \(x\) can be neglected, the coefficient of \(x\) in \(\frac{(1-x)^{1 / 3}+(1-5 x)^2}{(16-x)^{1 / 4}}\) is equal to
- A \(\frac{989}{96}\)
- B \(\frac{989}{192}\)
- C \(-\frac{989}{96}\)
- D \(-\frac{989}{192}\)
Answer & Solution
Correct Answer
(D) \(-\frac{989}{192}\)
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