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AP EAMCET · Maths · Properties of Triangles

In \(\triangle \mathrm{ABC}\), if \(a=2(\sqrt{3}+1), B=45^{\circ}\) and \(C=60^{\circ}\), then the area (in sq.units) of that triangle is

  1. A \(2 \sqrt{3}\)
  2. B \(6\)
  3. C \(6+2 \sqrt{3}\)
  4. D \(6-2 \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(6+2 \sqrt{3}\)

Step-by-step Solution

Detailed explanation

\(A = 180^{\circ} - 45^{\circ} - 60^{\circ} = 75^{\circ}\) \(b = \frac{a \sin B}{\sin A} = \frac{2(\sqrt{3}+1) \sin 45^{\circ}}{\sin 75^{\circ}}\)…