AP EAMCET · Maths · Properties of Triangles
In \(\triangle A B C\), if \(a=13 \mathrm{~cm}, b=14 \mathrm{~cm}\) and \(c=15 \mathrm{~cm}\) then its circumradius, \(R=\)
- A \(\frac{8}{65} \mathrm{~cm}\)
- B \(\frac{7}{65} \mathrm{~cm}\)
- C \(\frac{65}{7} \mathrm{~cm}\)
- D \(\frac{65}{8} \mathrm{~cm}\)
Answer & Solution
Correct Answer
(D) \(\frac{65}{8} \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
\( s = \frac{a+b+c}{2} = \frac{13+14+15}{2} = 21 \) \( K = \sqrt{s(s-a)(s-b)(s-c)} = \sqrt{21(21-13)(21-14)(21-15)} = \sqrt{21 \cdot 8 \cdot 7 \cdot 6} = \sqrt{7056} = 84 \)…
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