AP EAMCET · Maths · Properties of Triangles
In \(\triangle \mathrm{ABC}\), if \(\mathrm{a}^2 \sin ^2 \frac{\mathrm{C}}{2}+\mathrm{c} \sin ^2 \frac{\mathrm{A}}{2}=\frac{\mathrm{b}}{2}\), then \(\mathrm{a}+\mathrm{c}: \mathrm{b}=\)
- A \(2: 1\)
- B \(1: 2\)
- C \(3: 2\)
- D \(4: 3\)
Answer & Solution
Correct Answer
(A) \(2: 1\)
Step-by-step Solution
Detailed explanation
\(\because a \sin ^2 \frac{C}{2}+C \sin ^2 \frac{A}{2}=\frac{b}{2}\)…
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