AP EAMCET · Maths · Circle
The area of an equilateral triangle inscribed in the circle \(x^2+y^2-6 x+2 y-28=0\) is sq. units
- A \(\frac{27 \sqrt{3}}{2}\)
- B \(\frac{37 \sqrt{3}}{2}\)
- C \(\frac{31 \sqrt{3}}{2}\)
- D \(\frac{57 \sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{57 \sqrt{3}}{2}\)
Step-by-step Solution
Detailed explanation
Equation of given circle is \(\begin{aligned} & & x^2+y^2-6 x+2 y-28 & =0 \\ \Rightarrow & & (x-3)^2+(y+1)^2 & =38 \end{aligned}\) Now, area of equilateral triangle…
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