AP EAMCET · PHYSICS · Magnetic Effects of Current
A particle of mass \(1 \times 10^{-27} \mathrm{~kg}\) and charge \(1 \times 10^{-16} \mathrm{C}\) enters the uniform magnetic field within the solenoid, at speed \(1000 \mathrm{~ms}^{-1}\). The velocity vector makcs an angle \(60^{\circ}\) with the axis of solenoid. The solenoid has 5000 turns along its length and carries current \(5 \mathrm{~A}\). The number of revolution the particle makes along the helical path within the solenoid by the time it emerges from solenoid's opposite end is
- A \(5 \times 10^5\)
- B \(1 \times 10^6\)
- C \(\pi \times 10^5\)
- D \(3 \times 10^6\)
Answer & Solution
Correct Answer
(B) \(1 \times 10^6\)
Step-by-step Solution
Detailed explanation
The given situation is shown below. Given, \(\begin{aligned} v & =1000 \mathrm{~m} / \mathrm{s} \\ q & =10^{-16} \mathrm{C} \\ m & =1 \times 10^{-27} \mathrm{~kg}\end{aligned}\)…
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