AP EAMCET · Maths · Straight Lines
In a triangle \(\mathrm{ABC}\), if \(\mathrm{a}-2 \mathrm{~b}+\mathrm{c}=0\), then \(\cot \left(\frac{A}{2}\right) \cdot \cot \left(\frac{C}{2}\right)=\)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
We are given that \(a-2 b+c=0 \Rightarrow 2 b=a+c\) \(\Rightarrow \mathrm{b}=\frac{\mathrm{a}+\mathrm{c}}{2}\) Now…
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