AP EAMCET · Maths · Indefinite Integration
\(\int \frac{1}{1+x+x^2} d x=\)
- A \(\frac{2}{\sqrt{3}} \log \left(\frac{2 x+1+\sqrt{3}}{2 x-1-\sqrt{3}}\right)+c\)
- B \(\frac{1}{\sqrt{3}} \log \left(\frac{2 x+1-\sqrt{3}}{2 x+1+\sqrt{3}}\right)+c\)
- C \(\frac{2}{\sqrt{3}} \operatorname{Tan}^{-1}\left(\frac{2 x+1}{\sqrt{3}}\right)+c\)
- D \(\frac{2}{\sqrt{5}} \operatorname{Tan}^{-1}\left(\frac{2 \mathrm{x}+1}{\sqrt{5}}\right)+\mathrm{c}\)
Answer & Solution
Correct Answer
(C) \(\frac{2}{\sqrt{3}} \operatorname{Tan}^{-1}\left(\frac{2 x+1}{\sqrt{3}}\right)+c\)
Step-by-step Solution
Detailed explanation
\(\int \frac{1}{x^2+x+1} dx = \int \frac{1}{\left(x+\frac{1}{2}\right)^2 + \left(\frac{\sqrt{3}}{2}\right)^2} dx\) \( = \frac{1}{\frac{\sqrt{3}}{2}} \operatorname{Tan}^{-1}\left(\frac{x+\frac{1}{2}}{\frac{\sqrt{3}}{2}}\right) + c\)…
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