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AP EAMCET · Maths · Properties of Triangles

In a triangle ABC, if ab,acosA-bcosBacosB-bcosA+cosC=

  1. A 0
  2. B 1
  3. C 2
  4. D -1
Verified Solution

Answer & Solution

Correct Answer

(A) 0

Step-by-step Solution

Detailed explanation

Given, Triangle ABC, To find the value of acosA-bcosBacosB-bcosA+cosC Using the sine rule we get, =2RsinAcosA-2RsinBcosB2RsinAcosB-2RsinBcosA+cosC =sin2A-sin2B2sinAcosB-sinBcosA+cosC =2sinA-BcosA+B2sinA-B+cosC =cosA+B+cosC =-cosC+cosC as A+B=π-C =0