AP EAMCET · Maths · Properties of Triangles
Let \(A B C\) be an acute-angled triangle with area \(R\). Then,
\[
\sqrt{a^2 b^2-4 R^2}+\sqrt{b^2 c^2-4 R^2}+\sqrt{c^2 a^2-4 R^2}=
\]
- A \(a+b+c\)
- B \(a^2+b^2+c^2\)
- C \(\frac{a^2+b^2+c^2}{2}\)
- D \(2\left(a^2+b^2+c^2\right)\)
Answer & Solution
Correct Answer
(C) \(\frac{a^2+b^2+c^2}{2}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \sqrt{a^2 b^2-4 R^2}=\sqrt{a^2 b^2-(a b \sin c)^2} . \\ & =a b \cos C \end{aligned} \] Similarly, \(\sqrt{b^2 c^2-4 R^2}=b c \cos A\) \[ \sqrt{c^2 a^2-4 R^2}=c a \cos B \] \(\therefore\) Given, expression…
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